Home

Algebra and Pre-Algebra Lessons

Algebra 1 | Pre-Algebra | Practice Tests | Algebra Readiness Test

Algebra E-Course and Homework Information

Algebra E-course Info | Log In to Algebra E-course | Homework Calculator

Formulas and Cheat Sheets

Formulas | Algebra Cheat Sheets
» » Solving Compound Inequalities

Solving Compound Inequalities

In our last lesson, we solved compound inequalities that involved the word "and". These are called conjunctions.

In this lesson, we are going to solve the other type of compound inequality that is called a disjunction. These are the compound inequalities that contains the word "or".

There is really only one method to solving disjunction compound inequalities because you must solve each inequality separately.

Let's take a look at an example together.

Compound Inequalities - Example 1

Solve and graph: y - 3 > 5 or y +3 < -2

We must solve each inequality separately and then graph the results on one graph.

Now do you see why this is called a disjunction? These two inequalities will not have solutions that overlap.

Let's take a look at one more example. Remember the rule: If you multiply or divide by a negative number, then you must reverse the inequality sign? Well, that rule still applies. Take a look..

Solving Compound Inequalities - Example 2

Solve and graph: -3x - 4 < -7 or -2x +1 > 5

Again, we must solve each inequality separately and then graph the solutions on the same number line.

That's our final lesson on compound inequalities. Hopefully you can now tell the difference between a conjunction (using the word "and") and a disjunction (using the word "or"). Check out our other inequality lessons below for a thorough study of inequalities.

Top of the Page

Custom Search