Equation in slope intercept form

How do you write an equation in slope intercept form of negative 3 and the points of 1 and 1?

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Equation in slope intercept form

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Jan 11, 2011
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by: Karin

Thank you for a great explanation.

You are exactly right, point-slope form is a great technique to use also.

I am so used to teaching Pre-Algebra and Beginning Algebra that I often forget to mention this formula. We taught this as an Algebra 2 skill.

Thank you for your great explanation!
Jan 11, 2011
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starstarstar 		Equation in Slope-Intercept Form
by: Algebra House

Since you are given the slope and a point, you could use the point-slope form: y - y1 = m(x - x1)

(1,1), m = -3 {given a point and a slope}
y - y1 = m(x - x1) {point-slope form}
y - 1 = -3(x - 1) {substituted in}
y - 1 = -3x + 3 {used distributive property}
y = -3x + 4 {added 1 to both sides}

This is the line in slope-intercept form, y = mx + b
May 16, 2010
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by: Karin

I'm assuming that you mean the slope of the line is 3 and the line passes through the point (1,1).

In this case, you know: m = 3 x = 1 y = 1
We need to find b in order to write an equation in slope intercept form: y = mx + b

So, we'll substitute the given values and solve for b.

y = mx + b
1 = 3(1)+b
1 = 3 + b
1-3 = 3-3 + b
-2 = b

Now we know that b = -2 and we knew that m = 3, so we can write the equation in slope intercept form:
y= mx + b
y = 3x -2

For more examples on writing an equation in slope intercept form given slope and a point, please visit the following page:

http://www.algebra-class.com/writing-linear-equations.html

Hope this helps,
Karin

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