Solving Quadratic Equations

A person plants two square plots for garden. the of the areas of both plots is 225 square feet. If the side of one plot is 3 feet longer than the side of the other one, find the length of the smaller plot.

Comments for
Solving Quadratic Equations

Average Rating starstarstarstarstar

Click here to add your own comments

Dec 10, 2010
Rating
starstarstarstarstar
Solving Quadratic Equations
by: Karin

In order to multiply (x+3)^2, you can use the foil technique.

(x+3)(x+3)
First distribute the first x throughout the second parenthesis:

Multiply x * x to get x^2
Multiply x * 3 to get 6x

Then distribute the 3 throughout the second parenthesis:

Multiply 3*x to get 3x
Multiply 3*3 to get 9.

Then combine 3x + 3x to get 6x

So you end up with
x^2 + 6x + 9

Since I can't use graphics in this application it is very difficult to explain in words. Take a look at the lesson on foil and it might help to explain this more clearly.

http://www.algebra-class.com/foil-method.html

I hope this helps,
Karin

Dec 10, 2010
Rating
starstarstarstarstar
hi
by: Anonymous

Sorry I was woundering how you got 9
right here 2X^2+6X+9=225
^
Right here

Dec 09, 2010
Rating
starstarstarstarstar
Solving Quadratic Equations
by: Karin

Let x = the side of the smaller plot.

Since the other plot is 3 feet longer, the second plot's length is x +3.

You know the area of the both plots is 225.

Therefore, we need to find the area of both plots and add them together to get 225.

Remember area of a square is s^2 or the side squared.

Plot 1 area + Plot 2 area = 225
x^2 + (x+3)^2 = 225

x^2 + x^2 + 6x + 9 = 225

Simplify:

2x^2 + 6x + 9 = 225

Now, set the equation equal to 0 by subtracting 225 from both sides.

2x^2 + 6x + 9 - 225 = 225 - 225

2x^2 + 6x -216 = 0

Now use the quadratic formula to solve.

a = 2, b = 6, c = -216

Use the following web page for examples on how to use the quadratic formula:

http://www.algebra-class.com/quadratic-formula.html

Your answer should end up to be 9 for the length of the shorter plot.

Good luck,
Karin

Click here to add your own comments


Having Trouble with Your Homework?

algebrator




[ ?] Subscribe To This Site

XML RSS
Add to Google
Add to My Yahoo!
Add to My MSN
Add to Newsgator
Subscribe with Bloglines


Enjoy This Site?
Then why not use the button below, to add us to your favorite bookmarking service?

| Homepage | Contact Me | Privacy Policy | Disclaimer |Affiliates



Return to top
Copyright© Algebra-class.com 2009.