Linear Systems of Equations
(Las vegas, nv, clark county)
I'm using graph and check to solve the linear system.
My first equation is: 2x-y=2
I changed it to: -y=(-2)x+2
What do I do with the minus sign?
Second equation is x=4
How do you find the slope with such little information?
Karin from Algebra Class Says:
These are great questions.
For the first equation, you can either find the x and y intercept or you can rewrite it in slope intercept form. It looks like you've chosen to rewrite it in slope intercept form.
You came up with: -y = -2x + 2. This is correct for the first step, but we must make y positive by multiplying everything by -1.
(-1)-y = -1(-2x +2)
This leaves you with:
y = 2x - 2
This should be easy to graph now. Your y-intercept is -2 and the slope is 2.
Your second equation is x = 4
This equation represents a vertical line. Every point on that line must have an x coordinate that is 4. Therefore, the line must be vertical.
I hope this helps!
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